JAXB: 使用JAXB标注POJO，进行XML转换

1. 编写简单的POJO，并添加基本的注解，类似于JPA，只有被@XmlRootElement标注的类才会处理：

package org.jack.jaxb;

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Jack {

	private String firstName;
	private String lastName;

	public String getFirstName() {
		return firstName;
	}

	public void setFirstName(String firstName) {
		this.firstName = firstName;
	}

	public String getLastName() {
		return lastName;
	}

	public void setLastName(String lastName) {
		this.lastName = lastName;
	}

}

2. 编写测试类，进行POJO与XML的转换：

package org.jack.jaxb;

import java.io.StringReader;
import java.io.StringWriter;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;

public class JAXBTest {
	
	public static void main(String[] args) throws Exception {
		JAXBContext context = JAXBContext.newInstance(Jack.class);
		Marshaller marshaller = context.createMarshaller();
		Unmarshaller unmarshaller = context.createUnmarshaller();
		
		Jack jack = new Jack();
		jack.setFirstName("jack");
		jack.setLastName("lee");
		
		StringWriter writer = new StringWriter();
		marshaller.marshal(jack, writer);
		System.out.println(writer.toString());
		
		
		String xml = "<jack><firstName>first</firstName><lastName>last</lastName></jack>";
		Jack xj = (Jack) unmarshaller.unmarshal(new StringReader(xml));
		System.out.println(xj.getFirstName());
		System.out.println(xj.getLastName());
	}

}

3. 查看输出结果：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?><jack><firstName>jack</firstName><lastName>lee</lastName></jack>
first
last